3D - 2

solve the equations (ax/2b)-(c/3d) + x = 1?

Public Comments

1. Assuming that a, b, c, and d are constants: ax/2b + x = c/3d + 1 = (c + 3d)/3d (ax + 2bx)/2b = (c + 3d)/3d x(a + 2b)/2b = (c + 3d)/3d x(a + 2b) = 2b(c + 3d)/3d x = [2b(c + 3d)] / [3d(a + 2b)]
2. looks to me like someone enrolled in some sort of college-over-the-internet course, and wants everyone else to help them with their home work. Yeah. Why dont you waste your time asking questions about time travel and different breeds of dogs to tie to trees and neglect, you maker of chicken wings. You bully of a nail biter and paint slinger across one's face which wasnt you at all but that very person himself. You 'extra goods inside' flurry eater and ohh ahh los quatros is soooo goood chips and salsa chimichanga white sauce fan fan go go table. You such and such. Yeah. Hit you where it hurts, I cried.